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General Overview
SP6125
Vout
CP1
2pF
RZ
CZ2
130pF
RZ2
200k
CZ
R1
300k, 1%
VFB
Vref =0.6V
R2
Error Amplif ier
Figure 1- RZ and CZ in conjunction with internal
compensation components form a Type-III compensation
Loop Compensation Example 1- A converter
utilizing a SP6125 has a 8.2uH inductor and
response of the circuit, seen in figure 2,
validates the above procedure.
two 22uF/5m
ceramic capacitor.
Loop Compensation Example 2- A converter
Determine whether Type-III compensation is
utilizing a SP6125 has a 8.2uH inductor and
needed.
a 150uF, 82m
Aluminum Electrolytic
capacitor. Determine whether Type-III
From equation (2) f ESRZERO = 1.45MHz. From
compensation is needed.
equation (3) f DBPOLE
= 8.4kHz. Since the
condition specified in (1) is not met, Type-III
From equation (2) f ESRZERO = 13kHz. From
compensation has to be used by adding
equation (3) f DBPOLE
= 4.5kHz. Since the
external components RZ and CZ. Using
equation (4) CZ is calculated 48.7pF (use 47
pF). Following the guideline given in table 1,
condition specified in (1) is not met, Type-III
compensation has to be used by adding
external components RZ and CZ. Using
a 2k
RZ should be used.
equation (4) CZ is calculated 89.9pF (use
The steps followed in example 1 were used
to compensate the typical application circuit
shown on page 1. Satisfactory frequency
100pF). Since f ESRZERO ÷ f DBPOLE
approximately 3, RZ has to be set at 30k .
is
Figure 2- Satisfactory frequency response of typical application circuit shown on page 1.
Crossover frequency fc is about 35kHz with a corresponding phase margin of 60 degrees. The
two sets of curves, which are essentially identical, correspond to load current of 1A and 2.5A.
Jan28-08 RevG
SP6125: TSOT-6 PFET Buck Controller
5
? 2007 Exar Corporation
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